1 points | by adletbalzhanov 2 hours ago
3 comments
I didn't read the article, I don't think these kind has any value, but if you are here.. :)
i think it is rather binary, so
P_overall_success = 1 - (1 - P_success) ^ #attempts
and expected number of first success:
n = 1 / P_success
I don't see "cost" mentioned anywhere there.
That determines how many attempts you can buy.
I didn't read the article, I don't think these kind has any value, but if you are here.. :)
i think it is rather binary, so
P_overall_success = 1 - (1 - P_success) ^ #attempts
and expected number of first success:
n = 1 / P_success
I don't see "cost" mentioned anywhere there.
That determines how many attempts you can buy.